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Antiderivative of f(x) = x² sin x³

This problem asks to find the antiderivative F(x) of the function f(x) = x² sin x³ satisfying the condition F(0) = 1/2.

Problem

f ( x ) = x2 sin x3 , F ( 0 ) = 12

Solution

Step 1

Note that the derivative of x³ is 3x². Therefore, d(x³) = 3x² dx. This allows us to bring the factor x² under the differential sign.

d ( x3 ) = 3 x2 d x

Step 2

Rewrite the original integral, extracting the factor 1/3:

∫ x2 sin x3 d x = 13 ∫ sin ( x3 ) d ( x3 )

Step 3

Perform the substitution t = x³. The integral then takes a tabular form:

13 ∫ sin t d t = − 13 cos t + C

Step 4

Return to the variable x:

F ( x ) = − 13 cos x3 + C

Step 5

Now find the constant C from the initial condition F(0) = 1/2. Substitute x = 0:

− 13 cos 0 + C = 12

Step 6

From this we get C = 5/6. The required antiderivative has the form:

Answer

F ( x ) = − 13 cos x3 + 56

  • Antiderivative and integral
  • Definite integral
  • Improper integrals
  • Double integrals
  • Triple integrals
  • Line integrals
  • Surface integrals
  • Elements of field theory