Antiderivative of f(x) = x² sin x³
This problem asks to find the antiderivative F(x) of the function f(x) = x² sin x³ satisfying the condition F(0) = 1/2.
Problem
Solution
Step 1
Note that the derivative of x³ is 3x². Therefore, d(x³) = 3x² dx. This allows us to bring the factor x² under the differential sign.
Step 2
Rewrite the original integral, extracting the factor 1/3:
Step 3
Perform the substitution t = x³. The integral then takes a tabular form:
Step 4
Return to the variable x:
Step 5
Now find the constant C from the initial condition F(0) = 1/2. Substitute x = 0:
Step 6
From this we get C = 5/6. The required antiderivative has the form:
Answer
Frequently asked questions
How do I find the antiderivative of f(x) = x² sin x³?
Use the substitution method. Note that d(x³) = 3x² dx, so the integral can be rewritten as (1/3) ∫ sin(x³) d(x³). Then apply the substitution t = x³, and the integral reduces to the tabular ∫ sin t dt.
Why is the constant C needed and how is it found?
The constant C appears in indefinite integration because the derivative of a constant is zero. Its value is determined from the initial condition — for example, F(0) = 1/2. Substitute x = 0 into the expression for F(x) and solve for C.
Why is the substitution t = x³ convenient in this problem?
The substitution t = x³ turns the difficult integral ∫ x² sin x³ dx into the tabular ∫ sin t dt. Without this substitution, the integral cannot be evaluated in elementary functions. The presence of the factor x², proportional to the derivative of x³, makes this substitution possible.
What is the difference between an antiderivative and an indefinite integral?
An indefinite integral is the family of all antiderivatives: ∫ f(x) dx = F(x) + C. An antiderivative with a specific value of C is one function from this family. The problem asks for the specific antiderivative satisfying the initial condition.
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